Auto regressive processes with exogenous input
With ARMA we model time-series: we analize the output of a system without observing any input.
In many application, however, we can observe an input process $u(t)$.
$$ y(t)=a_1y(t-1)+...+a_my(t-m)+\newline b_0u(t-d)+b_1u(t-d-1)+...+b_pu(t-d-p)+\newline c_0e(t)+c_1e(t-1)+...+c_ne(t-n) $$ Where $d$ is the delay between input and output.
We denote $ARMAX(m,p,n)$ and $ARX(m,p)=ARMAX(m,p,0)$
Operatorial notation
If we use the shift operator we can define: $$A(z)=1-a_1z^{-1}-...-a_mz^{-m}$$ $$B(z)=b_0+b_1z^{-1}+...+b_pz^{-p}$$ $$C(z)=c_0+c_1z^{-1}+...+c_nz^{-n}$$
Which gives the recursive equation: $$A(z)y(t)=B(z)u(t-d)+C(z)e(t)$$
And the ARMAX process is the steady state solution of the recursive equation: $$y(t)=\frac{B(z)}{A(z)}u(t-d)+\frac{C(z)}{A(z)}e(t)$$
Note that the resulting ARMAX is the sum of:
- A deterministic part $\frac{B(z)}{A(z)}u(t-d)$
- A stochastic part $\frac{C(z)}{A(z)}e(t)$ which is an ARMA process
On the other hand, an ARX process is: $$y(t)=\frac{B(z)}{A(z)}u(t-d)+\frac{1}{A(z)}e(t)$$ Where the stochastic part is an AR process.
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